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直达:
Given a binary tree, determine if it is height-balanced.
For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees ofeverynode never differ by more than 1.
平衡二叉树的两棵子树的高度差小于2且左右两棵子树都是平衡二叉树,递归的判断即可。另外,树的高度也可以通过递归进行计算。
/** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: bool isBalanced(TreeNode* root) { if(!root) return true; if(abs(treeHeight(root->left) - treeHeight(root->right)) >= 2) return false; return isBalanced(root->left) && isBalanced(root->right); } private: int treeHeight(TreeNode* root){ if (!root) return 0; return max(treeHeight(root->left), treeHeight(root->right))+1; } };